What are the solutions to the equation 0=-4.9t^2+40t ?

The solutions to the equation 0=-4.9t^2+40t are t=0,t= 400/49

Find the zeros of 0=-4.9t^2+40t

The zeros of 0=-4.9t^2+40t are t=0,t= 400/49

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0 = - 4.9 t^{2} + 40 t

t = 0, t = \frac{400}{49}

Decimal Notation

t = 0, t = 8.16326 \dots

Solution steps

0 = - 4.9 t^{2} + 40 t

Multiply both sides by

10

0 = - 49 t^{2} + 400 t

Switch sides

- 49 t^{2} + 400 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 400 \pm 40 0 ^{2} - 4 ( - 49 ) \cdot 0}{2 ( - 49 )}

40 0^{2} - 4 (- 49) \cdot 0 = 400

t_{1, 2} = \frac{- 400 \pm 400}{2 ( - 49 )}

Separate the solutions

t_{1} = \frac{- 400 + 400}{2 ( - 49 )}, t_{2} = \frac{- 400 - 400}{2 ( - 49 )}

t = \frac{- 400 + 400}{2 ( - 49 )} : 0

t = \frac{- 400 - 400}{2 ( - 49 )} : \frac{400}{49}

The solutions to the quadratic equation are:

t = 0, t = \frac{400}{49}

24 n^{2} + 6 n = 0

0 = - 16 t^{2} + 100 t + 23

6 x^{2} + 384 = 0

(x + 8) (x - 2) = 0

(x - 4) (2 x + 3) = 0

What are the solutions to the equation 0=-4.9t^2+40t ?
The solutions to the equation 0=-4.9t^2+40t are t=0,t= 400/49
Find the zeros of 0=-4.9t^2+40t
The zeros of 0=-4.9t^2+40t are t=0,t= 400/49