What is (17x^0y^{-8})/(4^{-2)z^{-6}} ?

The solution to (17x^0y^{-8})/(4^{-2)z^{-6}} is (272z^6)/(y^8)

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simplify (17x^0y^{-8})/(4^{-2)z^{-6}}

simplify

\frac{17 x ^{0} y ^{- 8}}{4 ^{- 2} z ^{- 6}}

\frac{272 z ^{6}}{y ^{8}}

Solution steps

\frac{17 x ^{0} y ^{- 8}}{4 ^{- 2} z ^{- 6}}

Simplify

17 x^{0} y^{- 8} : \frac{17}{y ^{8}}

= \frac{\frac{17}{y ^{8}}}{4 ^{- 2} z ^{- 6}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{17}{y ^{8} \cdot 4 ^{- 2} z ^{- 6}}

Simplify

y^{8} \cdot 4^{- 2} z^{- 6} : \frac{y ^{8}}{16 z ^{6}}

= \frac{17}{\frac{y ^{8}}{16 z ^{6}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{17 \cdot 16 z ^{6}}{y ^{8}}

Multiply the numbers:

17 \cdot 16 = 272

= \frac{272 z ^{6}}{y ^{8}}

2 x^{2} - 4 x - 70

lo g_{3} (7 x - 6) < lo g_{3} (4 x + 9)

(\frac{1}{2})^{2} + (\frac{1}{2})^{2}

\frac{3 - \frac{1}{3} x}{3 + \frac{1}{2}} \geq \frac{3 x - \frac{5}{2}}{1 - \frac{2}{3}}

- 2 (5 + 6 c) + 16 = - 90

What is (17x^0y^{-8})/(4^{-2)z^{-6}} ?
The solution to (17x^0y^{-8})/(4^{-2)z^{-6}} is (272z^6)/(y^8)