What are the solutions to the equation (x^2-9x)+(11x+12)=180 ?

The solutions to the equation (x^2-9x)+(11x+12)=180 are x=12,x=-14

Find the zeros of (x^2-9x)+(11x+12)=180

The zeros of (x^2-9x)+(11x+12)=180 are x=12,x=-14

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(x^{2} - 9 x) + (11 x + 12) = 180

x = 12, x = - 14

Solution steps

(x^{2} - 9 x) + (11 x + 12) = 180

Refine

x^{2} + 2 x + 12 = 180

Move

180

to the left side

x^{2} + 2 x - 168 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 168 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 168) = 26

x_{1, 2} = \frac{- 2 \pm 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 26}{2 \cdot 1}, x_{2} = \frac{- 2 - 26}{2 \cdot 1}

x = \frac{- 2 + 26}{2 \cdot 1} : 12

x = \frac{- 2 - 26}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

x = 12, x = - 14

b^{2} + 19 b

x^{2} - 6 x = 0

x, \frac{x ^{2}}{4} + \frac{y ^{2}}{9} - \frac{z ^{2}}{25} = 0

x, z = x^{2} - 4 x y + y^{2} - 6 y

x, x^{2} + y^{2} - 12 x + 14 y + 85 = 0

What are the solutions to the equation (x^2-9x)+(11x+12)=180 ?
The solutions to the equation (x^2-9x)+(11x+12)=180 are x=12,x=-14
Find the zeros of (x^2-9x)+(11x+12)=180
The zeros of (x^2-9x)+(11x+12)=180 are x=12,x=-14