What are the solutions to the equation x^2+18x=-17 ?

The solutions to the equation x^2+18x=-17 are x=-1,x=-17

Find the zeros of x^2+18x=-17

The zeros of x^2+18x=-17 are x=-1,x=-17

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x^{2} + 18 x = - 17

x = - 1, x = - 17

Solution steps

x^{2} + 18 x = - 17

Move

17

to the left side

x^{2} + 18 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 17 = 16

x_{1, 2} = \frac{- 18 \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 16}{2 \cdot 1}, x_{2} = \frac{- 18 - 16}{2 \cdot 1}

x = \frac{- 18 + 16}{2 \cdot 1} : - 1

x = \frac{- 18 - 16}{2 \cdot 1} : - 17

The solutions to the quadratic equation are:

x = - 1, x = - 17

8 x^{2} - 1 - x = - x + 5

x^{2} + 18 x = - 45

(x - 5)^{2} + 17 = 9

x^{2} - 12 x + 9 = 0

5 x^{2} + 36 x - 32 = 0

What are the solutions to the equation x^2+18x=-17 ?
The solutions to the equation x^2+18x=-17 are x=-1,x=-17
Find the zeros of x^2+18x=-17
The zeros of x^2+18x=-17 are x=-1,x=-17