What are the solutions to the equation 2x^2=x^2+x ?

The solutions to the equation 2x^2=x^2+x are x=0,x=1

Find the zeros of 2x^2=x^2+x

The zeros of 2x^2=x^2+x are x=0,x=1

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2 x^{2} = x^{2} + x

x = 0, x = 1

Solution steps

2 x^{2} = x^{2} + x

Switch sides

x^{2} + x = 2 x^{2}

Move

2 x^{2}

to the left side

- x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 ( - 1 )}, x_{2} = \frac{- 1 - 1}{2 ( - 1 )}

x = \frac{- 1 + 1}{2 ( - 1 )} : 0

x = \frac{- 1 - 1}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = 0, x = 1

21 x^{2} - x - 2 = 0

3 (- x^{2} - 1) = 0

6 x^{2} = 9 x

s^{2} - 2 s + 4 = 0

1 = 3 x^{2}

What are the solutions to the equation 2x^2=x^2+x ?
The solutions to the equation 2x^2=x^2+x are x=0,x=1
Find the zeros of 2x^2=x^2+x
The zeros of 2x^2=x^2+x are x=0,x=1