What are the solutions to the equation 0=-x^2+4x-4 ?

The solutions to the equation 0=-x^2+4x-4 are x=2

Find the zeros of 0=-x^2+4x-4

The zeros of 0=-x^2+4x-4 are x=2

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0 = - x^{2} + 4 x - 4

x = 2

Solution steps

0 = - x^{2} + 4 x - 4

Switch sides

- x^{2} + 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

4^{2} - 4 (- 1) (- 4) = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 ( - 1 )}

x = \frac{- 4}{2 ( - 1 )}

\frac{- 4}{2 ( - 1 )} = 2

x = 2

The solution to the quadratic equation is:

x = 2

3 x^{2} + 4 x

x^{2} + \frac{2}{3} x - \frac{2}{9} = 0

5 r^{2} - 7 r + 8 = r^{2} + 16 r + 14

4 x^{2} + 4 x - 2 = 7 x

6 x (1 - x) = x

What are the solutions to the equation 0=-x^2+4x-4 ?
The solutions to the equation 0=-x^2+4x-4 are x=2
Find the zeros of 0=-x^2+4x-4
The zeros of 0=-x^2+4x-4 are x=2