What are the solutions to the equation x^2+50x=0 ?

The solutions to the equation x^2+50x=0 are x=0,x=-50

Find the zeros of x^2+50x=0

The zeros of x^2+50x=0 are x=0,x=-50

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x^{2} + 50 x = 0

x = 0, x = - 50

Solution steps

x^{2} + 50 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

5 0^{2} - 4 \cdot 1 \cdot 0 = 50

x_{1, 2} = \frac{- 50 \pm 50}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 50 + 50}{2 \cdot 1}, x_{2} = \frac{- 50 - 50}{2 \cdot 1}

x = \frac{- 50 + 50}{2 \cdot 1} : 0

x = \frac{- 50 - 50}{2 \cdot 1} : - 50

The solutions to the quadratic equation are:

x = 0, x = - 50

(2 x - 3)^{2} - (x + 5)^{2} = 23

x, 0 = x^{2} - 2 x - 3

(2 a)^{2} + a^{2} + (a - 1)^{2} = (a + 1)^{2} + (a - 2)^{2}

7 x^{2} + 30 x - 25 = 0

- 2 x^{2} - 5 x + 4 = 0

What are the solutions to the equation x^2+50x=0 ?
The solutions to the equation x^2+50x=0 are x=0,x=-50
Find the zeros of x^2+50x=0
The zeros of x^2+50x=0 are x=0,x=-50