What are the solutions to the equation X^2+2X+1=3X-10 ?

The solutions to the equation X^2+2X+1=3X-10 are X= 1/2+i(sqrt(43))/2 ,X= 1/2-i(sqrt(43))/2

Find the zeros of X^2+2X+1=3X-10

The zeros of X^2+2X+1=3X-10 are X= 1/2+i(sqrt(43))/2 ,X= 1/2-i(sqrt(43))/2

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X^{2} + 2 X + 1 = 3 X - 10

X = \frac{1}{2} + i \frac{43}{2}, X = \frac{1}{2} - i \frac{43}{2}

Solution steps

X^{2} + 2 X + 1 = 3 X - 10

Move

10

to the left side

X^{2} + 2 X + 11 = 3 X

Move

3 X

to the left side

X^{2} - X + 11 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 11 : 43 i

X_{1, 2} = \frac{- ( - 1 ) \pm 43 i}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- ( - 1 ) + 43 i}{2 \cdot 1}, X_{2} = \frac{- ( - 1 ) - 43 i}{2 \cdot 1}

X = \frac{- ( - 1 ) + 43 i}{2 \cdot 1} : \frac{1}{2} + i \frac{43}{2}

X = \frac{- ( - 1 ) - 43 i}{2 \cdot 1} : \frac{1}{2} - i \frac{43}{2}

The solutions to the quadratic equation are:

X = \frac{1}{2} + i \frac{43}{2}, X = \frac{1}{2} - i \frac{43}{2}

(x + 4) 2 = 2 x (5 x - 1) - 7 (x - 2)

x^{2} - 6 x + 8 = 0

0 = x^{2} - 6 x + 4

14 x^{2} + 73 x - 22 = 0

6 x^{2} + x - 12 = 0

What are the solutions to the equation X^2+2X+1=3X-10 ?
The solutions to the equation X^2+2X+1=3X-10 are X= 1/2+i(sqrt(43))/2 ,X= 1/2-i(sqrt(43))/2
Find the zeros of X^2+2X+1=3X-10
The zeros of X^2+2X+1=3X-10 are X= 1/2+i(sqrt(43))/2 ,X= 1/2-i(sqrt(43))/2