What are the solutions to the equation y^2=16y ?

The solutions to the equation y^2=16y are y=16,y=0

Find the zeros of y^2=16y

The zeros of y^2=16y are y=16,y=0

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y^{2} = 16 y

y = 16, y = 0

Solution steps

y^{2} = 16 y

Move

16 y

to the left side

y^{2} - 16 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 0 = 16

y_{1, 2} = \frac{- ( - 16 ) \pm 16}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 16 ) + 16}{2 \cdot 1}, y_{2} = \frac{- ( - 16 ) - 16}{2 \cdot 1}

y = \frac{- ( - 16 ) + 16}{2 \cdot 1} : 16

y = \frac{- ( - 16 ) - 16}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

y = 16, y = 0

x^{2} - 5 x + 4 = 0

(- 2 x + 3) (- x + 3) = 0

9 x^{2} + 6 x - 18 = 0

x^{2} - 6 = 16 x + 30

x^{2} - 26 = 0

What are the solutions to the equation y^2=16y ?
The solutions to the equation y^2=16y are y=16,y=0
Find the zeros of y^2=16y
The zeros of y^2=16y are y=16,y=0