What are the solutions to the equation 4x^2+8x-252=0 ?

The solutions to the equation 4x^2+8x-252=0 are x=7,x=-9

Find the zeros of 4x^2+8x-252=0

The zeros of 4x^2+8x-252=0 are x=7,x=-9

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4 x^{2} + 8 x - 252 = 0

x = 7, x = - 9

Solution steps

4 x^{2} + 8 x - 252 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 ( - 252 )}{2 \cdot 4}

8^{2} - 4 \cdot 4 (- 252) = 64

x_{1, 2} = \frac{- 8 \pm 64}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 64}{2 \cdot 4}, x_{2} = \frac{- 8 - 64}{2 \cdot 4}

x = \frac{- 8 + 64}{2 \cdot 4} : 7

x = \frac{- 8 - 64}{2 \cdot 4} : - 9

The solutions to the quadratic equation are:

x = 7, x = - 9

- 3 x \cdot (2 x - 1) = 0

x^{2} + 3 x - 4 = 0

2 x^{2} - x + 4 = x^{2} + 6 x - 6

x^{2} = 52

0 = - x^{2} + 6 x - 9

What are the solutions to the equation 4x^2+8x-252=0 ?
The solutions to the equation 4x^2+8x-252=0 are x=7,x=-9
Find the zeros of 4x^2+8x-252=0
The zeros of 4x^2+8x-252=0 are x=7,x=-9