What are the solutions to the equation solvefor x,x^2+y^3=12 ?

The solutions to the equation solvefor x,x^2+y^3=12 are x=sqrt(12-y^3),x=-sqrt(12-y^3)

Find the zeros of solvefor x,x^2+y^3=12

The zeros of solvefor x,x^2+y^3=12 are x=sqrt(12-y^3),x=-sqrt(12-y^3)

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solve for

x, x^{2} + y^{3} = 12

x = 12 - y^{3}, x = - 12 - y^{3}

Solution steps

x^{2} + y^{3} = 12

Move

y^{3}

to the right side

x^{2} = 12 - y^{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 12 - y^{3}, x = - 12 - y^{3}

x^{2} - 7 x = - 9 x - 2

x^{2} = 97

x^{2} = 70

t^{2} - 2 t - 1 = 0

x, f = 3 x^{2} y + 5 x y^{3} - 3 x z

What are the solutions to the equation solvefor x,x^2+y^3=12 ?
The solutions to the equation solvefor x,x^2+y^3=12 are x=sqrt(12-y^3),x=-sqrt(12-y^3)
Find the zeros of solvefor x,x^2+y^3=12
The zeros of solvefor x,x^2+y^3=12 are x=sqrt(12-y^3),x=-sqrt(12-y^3)