What are the solutions to the equation -13=x^2-4x ?

The solutions to the equation -13=x^2-4x are x=2+3i,x=2-3i

Find the zeros of -13=x^2-4x

The zeros of -13=x^2-4x are x=2+3i,x=2-3i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 13 = x^{2} - 4 x

x = 2 + 3 i, x = 2 - 3 i

Solution steps

- 13 = x^{2} - 4 x

Switch sides

x^{2} - 4 x = - 13

Move

13

to the left side

x^{2} - 4 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 13 : 6 i

x_{1, 2} = \frac{- ( - 4 ) \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6 i}{2 \cdot 1} : 2 + 3 i

x = \frac{- ( - 4 ) - 6 i}{2 \cdot 1} : 2 - 3 i

The solutions to the quadratic equation are:

x = 2 + 3 i, x = 2 - 3 i

160 - 104 x + 12 x^{2} = 0

\frac{1}{2} x^{2} + \frac{1}{4} x - \frac{1}{6} = 0

n^{2} - 16 = 0

x^{2} + 10 x + 25

x^{2} - 2 x + 1 = 0

What are the solutions to the equation -13=x^2-4x ?
The solutions to the equation -13=x^2-4x are x=2+3i,x=2-3i
Find the zeros of -13=x^2-4x
The zeros of -13=x^2-4x are x=2+3i,x=2-3i