What are the solutions to the equation x^2-5x^2+4=0 ?

The solutions to the equation x^2-5x^2+4=0 are x=1,x=-1

Find the zeros of x^2-5x^2+4=0

The zeros of x^2-5x^2+4=0 are x=1,x=-1

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x^{2} - 5 x^{2} + 4 = 0

x = 1, x = - 1

Solution steps

x^{2} - 5 x^{2} + 4 = 0

Move

4

to the right side

x^{2} - 5 x^{2} = - 4

Add similar elements:

x^{2} - 5 x^{2} = - 4 x^{2}

- 4 x^{2} = - 4

Divide both sides by

- 4

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

- x^{2} - 12 x - 32 = 0

(2 x - 9)^{2} - 1 = 35

x^{2} + 9 x - 15 = 0

x^{2} - 8 x + 23 = 0

x^{2} + 18 x + 66 = 0

What are the solutions to the equation x^2-5x^2+4=0 ?
The solutions to the equation x^2-5x^2+4=0 are x=1,x=-1
Find the zeros of x^2-5x^2+4=0
The zeros of x^2-5x^2+4=0 are x=1,x=-1