What are the solutions to the equation solvefor x,(x-2)^2+y^2=4 ?

The solutions to the equation solvefor x,(x-2)^2+y^2=4 are x=sqrt(4-y^2)+2,x=-sqrt(4-y^2)+2

Find the zeros of solvefor x,(x-2)^2+y^2=4

The zeros of solvefor x,(x-2)^2+y^2=4 are x=sqrt(4-y^2)+2,x=-sqrt(4-y^2)+2

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solve for

x, (x - 2)^{2} + y^{2} = 4

x = 4 - y^{2} + 2, x = - 4 - y^{2} + 2

Solution steps

(x - 2)^{2} + y^{2} = 4

Move

y^{2}

to the right side

(x - 2)^{2} = 4 - y^{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 4 - y^{2} : x = 4 - y^{2} + 2

Solve

x - 2 = - 4 - y^{2} : x = - 4 - y^{2} + 2

The solutions to the quadratic equation are:

x = 4 - y^{2} + 2, x = - 4 - y^{2} + 2

(2 x - 5) (x + 1) = 2

5 x^{2} - 20 x - 25 = 0

5 x^{2} + 8 x = - 5

x, y^{2} x^{2} - 4 x^{2} - 4 y^{2} = 0

0 = x^{2} + 7 x + 10

What are the solutions to the equation solvefor x,(x-2)^2+y^2=4 ?
The solutions to the equation solvefor x,(x-2)^2+y^2=4 are x=sqrt(4-y^2)+2,x=-sqrt(4-y^2)+2
Find the zeros of solvefor x,(x-2)^2+y^2=4
The zeros of solvefor x,(x-2)^2+y^2=4 are x=sqrt(4-y^2)+2,x=-sqrt(4-y^2)+2