What are the solutions to the equation 3x^2-6x-36=0 ?

The solutions to the equation 3x^2-6x-36=0 are x=1+sqrt(13),x=1-sqrt(13)

Find the zeros of 3x^2-6x-36=0

The zeros of 3x^2-6x-36=0 are x=1+sqrt(13),x=1-sqrt(13)

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3 x^{2} - 6 x - 36 = 0

x = 1 + 13, x = 1 - 13

Decimal Notation

x = 4.60555 \dots, x = - 2.60555 \dots

Solution steps

3 x^{2} - 6 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 36 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 36) = 613

x_{1, 2} = \frac{- ( - 6 ) \pm 6 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 13}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 6 13}{2 \cdot 3}

x = \frac{- ( - 6 ) + 6 13}{2 \cdot 3} : 1 + 13

x = \frac{- ( - 6 ) - 6 13}{2 \cdot 3} : 1 - 13

The solutions to the quadratic equation are:

x = 1 + 13, x = 1 - 13

(x - 6)^{2} = 20

(x - 6)^{2} = 12

(x - 6)^{2} = - 4

2 x^{2} - 11 x = - 15

(x - 6)^{2} = 45

What are the solutions to the equation 3x^2-6x-36=0 ?
The solutions to the equation 3x^2-6x-36=0 are x=1+sqrt(13),x=1-sqrt(13)
Find the zeros of 3x^2-6x-36=0
The zeros of 3x^2-6x-36=0 are x=1+sqrt(13),x=1-sqrt(13)