What are the solutions to the equation m^2-4m-91=0 ?

The solutions to the equation m^2-4m-91=0 are m=2+sqrt(95),m=2-sqrt(95)

Find the zeros of m^2-4m-91=0

The zeros of m^2-4m-91=0 are m=2+sqrt(95),m=2-sqrt(95)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{2} - 4 m - 91 = 0

m = 2 + 95, m = 2 - 95

Decimal Notation

m = 11.74679 \dots, m = - 7.74679 \dots

Solution steps

m^{2} - 4 m - 91 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 91 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 91) = 295

m_{1, 2} = \frac{- ( - 4 ) \pm 2 95}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 4 ) + 2 95}{2 \cdot 1}, m_{2} = \frac{- ( - 4 ) - 2 95}{2 \cdot 1}

m = \frac{- ( - 4 ) + 2 95}{2 \cdot 1} : 2 + 95

m = \frac{- ( - 4 ) - 2 95}{2 \cdot 1} : 2 - 95

The solutions to the quadratic equation are:

m = 2 + 95, m = 2 - 95

4 y^{2} - 7 y = 0

3 x^{2} = 10 - 13 x

x, f = x^{2} + 2 m x - m

6 x^{2} + 5 x - 25 = 0

λ^{2} - λ - 2 = 0

What are the solutions to the equation m^2-4m-91=0 ?
The solutions to the equation m^2-4m-91=0 are m=2+sqrt(95),m=2-sqrt(95)
Find the zeros of m^2-4m-91=0
The zeros of m^2-4m-91=0 are m=2+sqrt(95),m=2-sqrt(95)