What are the solutions to the equation (x-2)^2-2(x-2)-15=0 ?

The solutions to the equation (x-2)^2-2(x-2)-15=0 are x=7,x=-1

Find the zeros of (x-2)^2-2(x-2)-15=0

The zeros of (x-2)^2-2(x-2)-15=0 are x=7,x=-1

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(x - 2)^{2} - 2 (x - 2) - 15 = 0

x = 7, x = - 1

Solution steps

(x - 2)^{2} - 2 (x - 2) - 15 = 0

Expand

(x - 2)^{2} - 2 (x - 2) - 15 : x^{2} - 6 x - 7

x^{2} - 6 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 7) = 8

x_{1, 2} = \frac{- ( - 6 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 8}{2 \cdot 1}

x = \frac{- ( - 6 ) + 8}{2 \cdot 1} : 7

x = \frac{- ( - 6 ) - 8}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 7, x = - 1

(5 c + 1)^{2} = - 27

3 x^{2} + 6 x + 18 = 0

a^{2} + 4 a + 1 = 0

4 x^{2} - 6 x + 16 = 0

x^{2} - 14 x + 67 = 0

What are the solutions to the equation (x-2)^2-2(x-2)-15=0 ?
The solutions to the equation (x-2)^2-2(x-2)-15=0 are x=7,x=-1
Find the zeros of (x-2)^2-2(x-2)-15=0
The zeros of (x-2)^2-2(x-2)-15=0 are x=7,x=-1