What are the solutions to the equation 4b^2+8b+7=0 ?

The solutions to the equation 4b^2+8b+7=0 are b=-1+i(sqrt(3))/2 ,b=-1-i(sqrt(3))/2

Find the zeros of 4b^2+8b+7=0

The zeros of 4b^2+8b+7=0 are b=-1+i(sqrt(3))/2 ,b=-1-i(sqrt(3))/2

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4 b^{2} + 8 b + 7 = 0

b = - 1 + i \frac{3}{2}, b = - 1 - i \frac{3}{2}

Solution steps

4 b^{2} + 8 b + 7 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 7}{2 \cdot 4}

Simplify

8^{2} - 4 \cdot 4 \cdot 7 : 43 i

b_{1, 2} = \frac{- 8 \pm 4 3 i}{2 \cdot 4}

Separate the solutions

b_{1} = \frac{- 8 + 4 3 i}{2 \cdot 4}, b_{2} = \frac{- 8 - 4 3 i}{2 \cdot 4}

b = \frac{- 8 + 4 3 i}{2 \cdot 4} : - 1 + i \frac{3}{2}

b = \frac{- 8 - 4 3 i}{2 \cdot 4} : - 1 - i \frac{3}{2}

The solutions to the quadratic equation are:

b = - 1 + i \frac{3}{2}, b = - 1 - i \frac{3}{2}

x^{2} + 2 x = 8

- 2 x^{2} - 16 x - 31

2 x^{2} = 18 x - 36

a^{2} - 6 a = - 8

7 x^{2} - x + 1 = 0

What are the solutions to the equation 4b^2+8b+7=0 ?
The solutions to the equation 4b^2+8b+7=0 are b=-1+i(sqrt(3))/2 ,b=-1-i(sqrt(3))/2
Find the zeros of 4b^2+8b+7=0
The zeros of 4b^2+8b+7=0 are b=-1+i(sqrt(3))/2 ,b=-1-i(sqrt(3))/2