What are the solutions to the equation m^2-2m+3=0 ?

The solutions to the equation m^2-2m+3=0 are m=1+sqrt(2)i,m=1-sqrt(2)i

Find the zeros of m^2-2m+3=0

The zeros of m^2-2m+3=0 are m=1+sqrt(2)i,m=1-sqrt(2)i

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m^{2} - 2 m + 3 = 0

m = 1 + 2 i, m = 1 - 2 i

Solution steps

m^{2} - 2 m + 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 3 : 22 i

m_{1, 2} = \frac{- ( - 2 ) \pm 2 2 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 2 ) + 2 2 i}{2 \cdot 1}, m_{2} = \frac{- ( - 2 ) - 2 2 i}{2 \cdot 1}

m = \frac{- ( - 2 ) + 2 2 i}{2 \cdot 1} : 1 + 2 i

m = \frac{- ( - 2 ) - 2 2 i}{2 \cdot 1} : 1 - 2 i

The solutions to the quadratic equation are:

m = 1 + 2 i, m = 1 - 2 i

x^{2} + 4 x - 2 = - 3 x - 2

- 2 x^{2} + 36 x = 0

b^{2} + 8 b + 15 = 0

k^{2} - 2 k - 15 = 0

9 x^{2} + 16 = - 24 x

What are the solutions to the equation m^2-2m+3=0 ?
The solutions to the equation m^2-2m+3=0 are m=1+sqrt(2)i,m=1-sqrt(2)i
Find the zeros of m^2-2m+3=0
The zeros of m^2-2m+3=0 are m=1+sqrt(2)i,m=1-sqrt(2)i