What are the solutions to the equation x^2+4m=-2(m-3) ?

The solutions to the equation x^2+4m=-2(m-3) are x=sqrt(-6m+6),x=-sqrt(-6m+6)

Find the zeros of x^2+4m=-2(m-3)

The zeros of x^2+4m=-2(m-3) are x=sqrt(-6m+6),x=-sqrt(-6m+6)

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x^{2} + 4 m = - 2 (m - 3)

x = - 6 m + 6, x = - - 6 m + 6

Solution steps

x^{2} + 4 m = - 2 (m - 3)

Move

4 m

to the right side

x^{2} = - 2 (m - 3) - 4 m

Simplify

- 2 (m - 3) - 4 m : - 6 m + 6

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 6 m + 6, x = - - 6 m + 6

3 x^{2} + 5 x - 2 = 0

36 x^{2} = 6 x

- 3 x^{2} - 8 x + 3 = 0

x^{2} + 21 x

x^{2} + 12 = 8 x - 4

What are the solutions to the equation x^2+4m=-2(m-3) ?
The solutions to the equation x^2+4m=-2(m-3) are x=sqrt(-6m+6),x=-sqrt(-6m+6)
Find the zeros of x^2+4m=-2(m-3)
The zeros of x^2+4m=-2(m-3) are x=sqrt(-6m+6),x=-sqrt(-6m+6)