What are the solutions to the equation quadraticformula x^2+2x-3=0 ?

The solutions to the equation quadraticformula x^2+2x-3=0 are x=1,x=-3

Find the zeros of quadraticformula x^2+2x-3=0

The zeros of quadraticformula x^2+2x-3=0 are x=1,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 2 x - 3 = 0

x = 1, x = - 3

Solution steps

x^{2} + 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 3) = 4

x_{1, 2} = \frac{- 2 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4}{2 \cdot 1}, x_{2} = \frac{- 2 - 4}{2 \cdot 1}

x = \frac{- 2 + 4}{2 \cdot 1} : 1

x = \frac{- 2 - 4}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

s^{2} + 2 s + 2 = 0

\frac{x}{3} = x^{2}

(2 x - 9) (x + 2) = 24

x, (x - y^{2}) (x + x y) = 4

w^{2} + 5 w - 6 = 0

What are the solutions to the equation quadraticformula x^2+2x-3=0 ?
The solutions to the equation quadraticformula x^2+2x-3=0 are x=1,x=-3
Find the zeros of quadraticformula x^2+2x-3=0
The zeros of quadraticformula x^2+2x-3=0 are x=1,x=-3