What are the solutions to the equation (x^2)/(10)-x/5 =1 ?

The solutions to the equation (x^2)/(10)-x/5 =1 are x=1+sqrt(11),x=1-sqrt(11)

Find the zeros of (x^2)/(10)-x/5 =1

The zeros of (x^2)/(10)-x/5 =1 are x=1+sqrt(11),x=1-sqrt(11)

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\frac{x ^{2}}{10} - \frac{x}{5} = 1

x = 1 + 11, x = 1 - 11

Decimal Notation

x = 4.31662 \dots, x = - 2.31662 \dots

Solution steps

\frac{x ^{2}}{10} - \frac{x}{5} = 1

Find Least Common Multiplier of

10, 5 : 10

Multiply by LCM=

10

\frac{x ^{2}}{10} \cdot 10 - \frac{x}{5} \cdot 10 = 1 \cdot 10

Simplify

x^{2} - 2 x = 10

Move

10

to the left side

x^{2} - 2 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 10) = 211

x_{1, 2} = \frac{- ( - 2 ) \pm 2 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 11}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 11}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 11}{2 \cdot 1} : 1 + 11

x = \frac{- ( - 2 ) - 2 11}{2 \cdot 1} : 1 - 11

The solutions to the quadratic equation are:

x = 1 + 11, x = 1 - 11

(x^{2} + 3 x) (m + 1) = (5 x + 12) (m - 1)

x (x + 5) = 234

x (x + 2) = 2 x + 9

- 24 x^{2} + 24 x = 0

6.3 \cdot 1 0^{- 5} = \frac{x ^{2}}{0.008}

What are the solutions to the equation (x^2)/(10)-x/5 =1 ?
The solutions to the equation (x^2)/(10)-x/5 =1 are x=1+sqrt(11),x=1-sqrt(11)
Find the zeros of (x^2)/(10)-x/5 =1
The zeros of (x^2)/(10)-x/5 =1 are x=1+sqrt(11),x=1-sqrt(11)