What are the solutions to the equation 12x^2-48x+35=0 ?

The solutions to the equation 12x^2-48x+35=0 are x=(12+sqrt(39))/6 ,x=(12-sqrt(39))/6

Find the zeros of 12x^2-48x+35=0

The zeros of 12x^2-48x+35=0 are x=(12+sqrt(39))/6 ,x=(12-sqrt(39))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 x^{2} - 48 x + 35 = 0

x = \frac{12 + 39}{6}, x = \frac{12 - 39}{6}

Solution steps

12 x^{2} - 48 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 12 \cdot 35}{2 \cdot 12}

(- 48)^{2} - 4 \cdot 12 \cdot 35 = 439

x_{1, 2} = \frac{- ( - 48 ) \pm 4 39}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 4 39}{2 \cdot 12}, x_{2} = \frac{- ( - 48 ) - 4 39}{2 \cdot 12}

x = \frac{- ( - 48 ) + 4 39}{2 \cdot 12} : \frac{12 + 39}{6}

x = \frac{- ( - 48 ) - 4 39}{2 \cdot 12} : \frac{12 - 39}{6}

The solutions to the quadratic equation are:

x = \frac{12 + 39}{6}, x = \frac{12 - 39}{6}

(6^{3})^{5}

x^{3} + 4 x^{2} - 9 x - 36

\frac{x}{2} - 1 = \frac{3 - x}{5}

7 b^{2} - 63 b + 140

9 = 5 y + 27 + 4 y

What are the solutions to the equation 12x^2-48x+35=0 ?
The solutions to the equation 12x^2-48x+35=0 are x=(12+sqrt(39))/6 ,x=(12-sqrt(39))/6
Find the zeros of 12x^2-48x+35=0
The zeros of 12x^2-48x+35=0 are x=(12+sqrt(39))/6 ,x=(12-sqrt(39))/6