What are the solutions to the equation 3y^2+14y=5 ?

The solutions to the equation 3y^2+14y=5 are y= 1/3 ,y=-5

Find the zeros of 3y^2+14y=5

The zeros of 3y^2+14y=5 are y= 1/3 ,y=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 y^{2} + 14 y = 5

y = \frac{1}{3}, y = - 5

Decimal Notation

y = 0.33333 \dots, y = - 5

Solution steps

3 y^{2} + 14 y = 5

Move

5

to the left side

3 y^{2} + 14 y - 5 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

1 4^{2} - 4 \cdot 3 (- 5) = 16

y_{1, 2} = \frac{- 14 \pm 16}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- 14 + 16}{2 \cdot 3}, y_{2} = \frac{- 14 - 16}{2 \cdot 3}

y = \frac{- 14 + 16}{2 \cdot 3} : \frac{1}{3}

y = \frac{- 14 - 16}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

y = \frac{1}{3}, y = - 5

S = U - N (N)

(x + 7)^{2} = - 4

x^{2} - 1.4 x + 0.4 = 0

x^{2} + 9 x + 20 = 0

a (x) = x^{2} - x + 7, a (1)

What are the solutions to the equation 3y^2+14y=5 ?
The solutions to the equation 3y^2+14y=5 are y= 1/3 ,y=-5
Find the zeros of 3y^2+14y=5
The zeros of 3y^2+14y=5 are y= 1/3 ,y=-5