What are the solutions to the equation 0=12x^2-204x+594 ?

The solutions to the equation 0=12x^2-204x+594 are x=(17+sqrt(91))/2 ,x=(17-sqrt(91))/2

Find the zeros of 0=12x^2-204x+594

The zeros of 0=12x^2-204x+594 are x=(17+sqrt(91))/2 ,x=(17-sqrt(91))/2

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0 = 12 x^{2} - 204 x + 594

x = \frac{17 + 91}{2}, x = \frac{17 - 91}{2}

Decimal Notation

x = 13.26969 \dots, x = 3.73030 \dots

Solution steps

0 = 12 x^{2} - 204 x + 594

Switch sides

12 x^{2} - 204 x + 594 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 204 ) \pm ( - 204 ) ^{2} - 4 \cdot 12 \cdot 594}{2 \cdot 12}

(- 204)^{2} - 4 \cdot 12 \cdot 594 = 1291

x_{1, 2} = \frac{- ( - 204 ) \pm 12 91}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 204 ) + 12 91}{2 \cdot 12}, x_{2} = \frac{- ( - 204 ) - 12 91}{2 \cdot 12}

x = \frac{- ( - 204 ) + 12 91}{2 \cdot 12} : \frac{17 + 91}{2}

x = \frac{- ( - 204 ) - 12 91}{2 \cdot 12} : \frac{17 - 91}{2}

The solutions to the quadratic equation are:

x = \frac{17 + 91}{2}, x = \frac{17 - 91}{2}

X^{2} - 2 X = 0

8 y^{2} - 24 y = 3

k^{2} - 2 k - 24 = 0

x^{2} - 6 = 2 x

1 5^{2} + 1 2^{2} = x^{2}

What are the solutions to the equation 0=12x^2-204x+594 ?
The solutions to the equation 0=12x^2-204x+594 are x=(17+sqrt(91))/2 ,x=(17-sqrt(91))/2
Find the zeros of 0=12x^2-204x+594
The zeros of 0=12x^2-204x+594 are x=(17+sqrt(91))/2 ,x=(17-sqrt(91))/2