What is (2x^4y^{-4})/(8x^7y^3) ?

The solution to (2x^4y^{-4})/(8x^7y^3) is 1/(4x^3y^7)

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simplify (2x^4y^{-4})/(8x^7y^3)

simplify

\frac{2 x ^{4} y ^{- 4}}{8 x ^{7} y ^{3}}

\frac{1}{4 x ^{3} y ^{7}}

Solution steps

\frac{2 x ^{4} y ^{- 4}}{8 x ^{7} y ^{3}}

Factor the number:

8 = 2 \cdot 4

= \frac{2 x ^{4} y ^{- 4}}{2 \cdot 4 x ^{7} y ^{3}}

Cancel the common factor:

2

= \frac{x ^{4} y ^{- 4}}{4 x ^{7} y ^{3}}

Simplify

\frac{x ^{4}}{x ^{7}} : \frac{1}{x ^{3}}

= \frac{y ^{- 4}}{4 x ^{3} y ^{3}}

Simplify

\frac{y ^{- 4}}{y ^{3}} : \frac{1}{y ^{7}}

= \frac{1}{4 x ^{3} y ^{7}}

(8 - 4 i)^{2}

\frac{3}{x + h} - \frac{3}{x}

7 y^{2} - 20 y - 3

514

x^{2} - 2 x + 3

What is (2x^4y^{-4})/(8x^7y^3) ?
The solution to (2x^4y^{-4})/(8x^7y^3) is 1/(4x^3y^7)