What are the solutions to the equation x^2-13x-72=-7x ?

The solutions to the equation x^2-13x-72=-7x are x=12,x=-6

Find the zeros of x^2-13x-72=-7x

The zeros of x^2-13x-72=-7x are x=12,x=-6

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x^{2} - 13 x - 72 = - 7 x

x = 12, x = - 6

Solution steps

x^{2} - 13 x - 72 = - 7 x

Move

7 x

to the left side

x^{2} - 6 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 72) = 18

x_{1, 2} = \frac{- ( - 6 ) \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 18}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 18}{2 \cdot 1}

x = \frac{- ( - 6 ) + 18}{2 \cdot 1} : 12

x = \frac{- ( - 6 ) - 18}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 12, x = - 6

x, (m^{2} x) (m x - 1) = m^{2} x + 5

n^{2} - 6 n - 16 = 0

x^{2} = 3^{2} + 2^{2}

x^{2} + 10 x + 24 = 0

x^{2} - \frac{1}{2} = 0

What are the solutions to the equation x^2-13x-72=-7x ?
The solutions to the equation x^2-13x-72=-7x are x=12,x=-6
Find the zeros of x^2-13x-72=-7x
The zeros of x^2-13x-72=-7x are x=12,x=-6