What are the solutions to the equation x^2+16x+16=0 ?

The solutions to the equation x^2+16x+16=0 are x=4(sqrt(3)-2),x=-4(2+sqrt(3))

Find the zeros of x^2+16x+16=0

The zeros of x^2+16x+16=0 are x=4(sqrt(3)-2),x=-4(2+sqrt(3))

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x^{2} + 16 x + 16 = 0

x = 4 (3 - 2), x = - 4 (2 + 3)

Decimal

x = - 1.07179 \dots, x = - 14.92820 \dots

Solution steps

x^{2} + 16 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 16 = 83

x_{1, 2} = \frac{- 16 \pm 8 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 8 3}{2 \cdot 1}, x_{2} = \frac{- 16 - 8 3}{2 \cdot 1}

x = \frac{- 16 + 8 3}{2 \cdot 1} : 4 (3 - 2)

x = \frac{- 16 - 8 3}{2 \cdot 1} : - 4 (2 + 3)

The solutions to the quadratic equation are:

x = 4 (3 - 2), x = - 4 (2 + 3)

4 x^{2} + 6 x + 9 = 3 x^{2}

\frac{x ^{2}}{6} = 38

5 x^{2} - 2 x - 16 = 0

(x - 8)^{2} = 7

250 = 0.0066 x^{2} + 4.0384 x + 19.145

What are the solutions to the equation x^2+16x+16=0 ?
The solutions to the equation x^2+16x+16=0 are x=4(sqrt(3)-2),x=-4(2+sqrt(3))
Find the zeros of x^2+16x+16=0
The zeros of x^2+16x+16=0 are x=4(sqrt(3)-2),x=-4(2+sqrt(3))