What are the solutions to the equation 4x^2+6x+9=3x^2 ?

The solutions to the equation 4x^2+6x+9=3x^2 are x=-3

Find the zeros of 4x^2+6x+9=3x^2

The zeros of 4x^2+6x+9=3x^2 are x=-3

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4 x^{2} + 6 x + 9 = 3 x^{2}

x = - 3

Solution steps

4 x^{2} + 6 x + 9 = 3 x^{2}

Move

3 x^{2}

to the left side

x^{2} + 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

x = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

x = - 3

The solution to the quadratic equation is:

x = - 3

\frac{x ^{2}}{6} = 38

5 x^{2} - 2 x - 16 = 0

(x - 8)^{2} = 7

250 = 0.0066 x^{2} + 4.0384 x + 19.145

x^{2} - 8 x + 36 = 0

What are the solutions to the equation 4x^2+6x+9=3x^2 ?
The solutions to the equation 4x^2+6x+9=3x^2 are x=-3
Find the zeros of 4x^2+6x+9=3x^2
The zeros of 4x^2+6x+9=3x^2 are x=-3