What are the solutions to the equation 16x^2-8x+4=0 ?

The solutions to the equation 16x^2-8x+4=0 are x= 1/4+i(sqrt(3))/4 ,x= 1/4-i(sqrt(3))/4

Find the zeros of 16x^2-8x+4=0

The zeros of 16x^2-8x+4=0 are x= 1/4+i(sqrt(3))/4 ,x= 1/4-i(sqrt(3))/4

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16 x^{2} - 8 x + 4 = 0

x = \frac{1}{4} + i \frac{3}{4}, x = \frac{1}{4} - i \frac{3}{4}

Solution steps

16 x^{2} - 8 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 16 \cdot 4}{2 \cdot 16}

Simplify

(- 8)^{2} - 4 \cdot 16 \cdot 4 : 83 i

x_{1, 2} = \frac{- ( - 8 ) \pm 8 3 i}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8 3 i}{2 \cdot 16}, x_{2} = \frac{- ( - 8 ) - 8 3 i}{2 \cdot 16}

x = \frac{- ( - 8 ) + 8 3 i}{2 \cdot 16} : \frac{1}{4} + i \frac{3}{4}

x = \frac{- ( - 8 ) - 8 3 i}{2 \cdot 16} : \frac{1}{4} - i \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} + i \frac{3}{4}, x = \frac{1}{4} - i \frac{3}{4}

x, x^{2} - 2 y - z^{2} + x^{2} y z^{2} = 20

2 x^{2} - 8 x + 12 = 0

6 x^{2} - 78 x + 180 = 0

x^{2} - 7 = 42

4 x = x^{2} + 7

What are the solutions to the equation 16x^2-8x+4=0 ?
The solutions to the equation 16x^2-8x+4=0 are x= 1/4+i(sqrt(3))/4 ,x= 1/4-i(sqrt(3))/4
Find the zeros of 16x^2-8x+4=0
The zeros of 16x^2-8x+4=0 are x= 1/4+i(sqrt(3))/4 ,x= 1/4-i(sqrt(3))/4