What are the solutions to the equation completesquare x^2-x/4 ?

The solutions to the equation completesquare x^2-x/4 are (x-1/8)^2-1/64

Find the zeros of completesquare x^2-x/4

The zeros of completesquare x^2-x/4 are (x-1/8)^2-1/64

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complete the square

x^{2} - \frac{x}{4}

(x - \frac{1}{8})^{2} - \frac{1}{64}

Solution steps

x^{2} - \frac{x}{4}

Write

x^{2} - \frac{x}{4}

in the form:

x^{2} + 2 a x + a^{2}

2 a = - \frac{1}{4} : a = - \frac{1}{8}

Add and subtract

(- \frac{1}{8})^{2}

x^{2} - \frac{x}{4} + (- \frac{1}{8})^{2} - (- \frac{1}{8})^{2}

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} - \frac{1}{4} x + (- \frac{1}{8})^{2} = (x - \frac{1}{8})^{2}

(x - \frac{1}{8})^{2} - (- \frac{1}{8})^{2}

Simplify

(x - \frac{1}{8})^{2} - \frac{1}{64}

x^{2} + x^{2} = 1 6^{2}

x^{2} + 8 x + 7 = 0

2 x^{2} - x - 6 = 0

740 - 228 x + 12 x^{2} = 0

0 = - 5 x^{2} - 125

What are the solutions to the equation completesquare x^2-x/4 ?
The solutions to the equation completesquare x^2-x/4 are (x-1/8)^2-1/64
Find the zeros of completesquare x^2-x/4
The zeros of completesquare x^2-x/4 are (x-1/8)^2-1/64