What are the solutions to the equation a^2+9a+20=0 ?

The solutions to the equation a^2+9a+20=0 are a=-4,a=-5

Find the zeros of a^2+9a+20=0

The zeros of a^2+9a+20=0 are a=-4,a=-5

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a^{2} + 9 a + 20 = 0

a = - 4, a = - 5

Solution steps

a^{2} + 9 a + 20 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 20 = 1

a_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 9 + 1}{2 \cdot 1}, a_{2} = \frac{- 9 - 1}{2 \cdot 1}

a = \frac{- 9 + 1}{2 \cdot 1} : - 4

a = \frac{- 9 - 1}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

a = - 4, a = - 5

- \frac{0.9 ( 5 )}{( 0.01 ( 5 ) ^{2} + 1 ) ^{2}}

9 x - 4 = 3 x - 16

(2 + 5 i) (3 + 4 i)

x^{2} + 4 x - 45 \geq 0

2 (\frac{3}{2}) - 3

What are the solutions to the equation a^2+9a+20=0 ?
The solutions to the equation a^2+9a+20=0 are a=-4,a=-5
Find the zeros of a^2+9a+20=0
The zeros of a^2+9a+20=0 are a=-4,a=-5