What are the solutions to the equation x^2-12x-91=-6 ?

The solutions to the equation x^2-12x-91=-6 are x=17,x=-5

Find the zeros of x^2-12x-91=-6

The zeros of x^2-12x-91=-6 are x=17,x=-5

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x^{2} - 12 x - 91 = - 6

x = 17, x = - 5

Solution steps

x^{2} - 12 x - 91 = - 6

Move

6

to the left side

x^{2} - 12 x - 85 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 85 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 85) = 22

x_{1, 2} = \frac{- ( - 12 ) \pm 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 22}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 22}{2 \cdot 1}

x = \frac{- ( - 12 ) + 22}{2 \cdot 1} : 17

x = \frac{- ( - 12 ) - 22}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 17, x = - 5

(x - 2)^{2} + 3 (3 x - 4) (3 x + 4) = 7 (4 x - 3) - 23

2 x^{2} - 13 x + 2 = 0

x^{2} - 10 x = 0

3 x^{2} - 4 x = 0

y, x^{2} + y^{2} = 16

What are the solutions to the equation x^2-12x-91=-6 ?
The solutions to the equation x^2-12x-91=-6 are x=17,x=-5
Find the zeros of x^2-12x-91=-6
The zeros of x^2-12x-91=-6 are x=17,x=-5