What are the solutions to the equation (x+3)(x-2)=-4 ?

The solutions to the equation (x+3)(x-2)=-4 are x=1,x=-2

Find the zeros of (x+3)(x-2)=-4

The zeros of (x+3)(x-2)=-4 are x=1,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 3) (x - 2) = - 4

x = 1, x = - 2

Solution steps

(x + 3) (x - 2) = - 4

Expand

(x + 3) (x - 2) : x^{2} + x - 6

x^{2} + x - 6 = - 4

Move

4

to the left side

x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2) = 3

x_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 3}{2 \cdot 1}, x_{2} = \frac{- 1 - 3}{2 \cdot 1}

x = \frac{- 1 + 3}{2 \cdot 1} : 1

x = \frac{- 1 - 3}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

(x + 4) 2 + 2 x = (x + 1) (x - 1) - 23

7^{2} + x^{2} = 8^{2}

x^{2} - 16 = 59

2 x^{2} + 3 - 2 = 0

- 25 x^{2} + 15 x - 2 = 0

What are the solutions to the equation (x+3)(x-2)=-4 ?
The solutions to the equation (x+3)(x-2)=-4 are x=1,x=-2
Find the zeros of (x+3)(x-2)=-4
The zeros of (x+3)(x-2)=-4 are x=1,x=-2