What is the answer to 3=1+|2-12y| ?

The answer to 3=1+|2-12y| is y=0\lor y= 1/3

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3=1+|2-12y|

3 = 1 + ∣ 2 - 12 y ∣

y = 0 or y = \frac{1}{3}

Solution steps

3 = 1 + ∣ 2 - 12 y ∣

Switch sides

1 + ∣ 2 - 12 y ∣ = 3

Move

1

to the right side

∣ 2 - 12 y ∣ = 2

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

2 - 12 y = - 2 or 2 - 12 y = 2

2 - 12 y = - 2 or 2 - 12 y = 2

y = 0 or y = \frac{1}{3}

f^{2} - 4 f + 3

(2 x + 1)^{2}

- 5 x^{- 3}

x - 3 = 4 x + 18

lo g_{2} (1.5)