What are the solutions to the equation (2x+5)^2=18 ?

The solutions to the equation (2x+5)^2=18 are x=(3sqrt(2)-5)/2 ,x=(-3sqrt(2)-5)/2

Find the zeros of (2x+5)^2=18

The zeros of (2x+5)^2=18 are x=(3sqrt(2)-5)/2 ,x=(-3sqrt(2)-5)/2

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(2 x + 5)^{2} = 18

x = \frac{3 2 - 5}{2}, x = \frac{- 3 2 - 5}{2}

Decimal Notation

x = - 0.37867 \dots, x = - 4.62132 \dots

Solution steps

(2 x + 5)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 5 = 18 : x = \frac{3 2 - 5}{2}

Solve

2 x + 5 = - 18 : x = \frac{- 3 2 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{3 2 - 5}{2}, x = \frac{- 3 2 - 5}{2}

7000 - 2 Q = 0.01 Q^{2} + 2 Q + 1000

x, 3 x^{2} - 2 y = 0

A, A (x) A (y) = A (x + y)

n^{2} + 4 n - 12 = 0

m^{2} + 2 m + 32 = 0

What are the solutions to the equation (2x+5)^2=18 ?
The solutions to the equation (2x+5)^2=18 are x=(3sqrt(2)-5)/2 ,x=(-3sqrt(2)-5)/2
Find the zeros of (2x+5)^2=18
The zeros of (2x+5)^2=18 are x=(3sqrt(2)-5)/2 ,x=(-3sqrt(2)-5)/2