What are the solutions to the equation x^2+1=17 ?

The solutions to the equation x^2+1=17 are x=4,x=-4

Find the zeros of x^2+1=17

The zeros of x^2+1=17 are x=4,x=-4

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x^{2} + 1 = 17

x = 4, x = - 4

Solution steps

x^{2} + 1 = 17

Move

1

to the right side

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

3 x^{2} - 2 x = - 4

y^{2} - 18 y = - 15

12 x^{2} - 72 x + 80 = 0

x, x^{2} + 2 = 0

x (5 x + 3) = 2

What are the solutions to the equation x^2+1=17 ?
The solutions to the equation x^2+1=17 are x=4,x=-4
Find the zeros of x^2+1=17
The zeros of x^2+1=17 are x=4,x=-4