What are the solutions to the equation x^2-3x+7=x+2 ?

The solutions to the equation x^2-3x+7=x+2 are x=2+i,x=2-i

Find the zeros of x^2-3x+7=x+2

The zeros of x^2-3x+7=x+2 are x=2+i,x=2-i

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x^{2} - 3 x + 7 = x + 2

x = 2 + i, x = 2 - i

Solution steps

x^{2} - 3 x + 7 = x + 2

Move

2

to the left side

x^{2} - 3 x + 5 = x

Move

x

to the left side

x^{2} - 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 5 : 2 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 i}{2 \cdot 1} : 2 + i

x = \frac{- ( - 4 ) - 2 i}{2 \cdot 1} : 2 - i

The solutions to the quadratic equation are:

x = 2 + i, x = 2 - i

\frac{1}{4} a^{2} + \frac{1}{8} a = 0

1 x^{2} - 2 x - 3 = 0

\frac{x ( x + 1 )}{2} = 91

x^{2} - x - 3

2 x^{2} - 5 x - 3

What are the solutions to the equation x^2-3x+7=x+2 ?
The solutions to the equation x^2-3x+7=x+2 are x=2+i,x=2-i
Find the zeros of x^2-3x+7=x+2
The zeros of x^2-3x+7=x+2 are x=2+i,x=2-i