What are the solutions to the equation X^2+4X-6=0 ?

The solutions to the equation X^2+4X-6=0 are X=-2+sqrt(10),X=-2-sqrt(10)

Find the zeros of X^2+4X-6=0

The zeros of X^2+4X-6=0 are X=-2+sqrt(10),X=-2-sqrt(10)

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X^{2} + 4 X - 6 = 0

X = - 2 + 10, X = - 2 - 10

Decimal Notation

X = 1.16227 \dots, X = - 5.16227 \dots

Solution steps

X^{2} + 4 X - 6 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 6) = 210

X_{1, 2} = \frac{- 4 \pm 2 10}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 4 + 2 10}{2 \cdot 1}, X_{2} = \frac{- 4 - 2 10}{2 \cdot 1}

X = \frac{- 4 + 2 10}{2 \cdot 1} : - 2 + 10

X = \frac{- 4 - 2 10}{2 \cdot 1} : - 2 - 10

The solutions to the quadratic equation are:

X = - 2 + 10, X = - 2 - 10

y, x = 2 (y - 1)^{2} + 2

x - 1 = x^{2}

s^{2} + 10 = 0

x^{2} = 60 + 4 x

n x^{2} + (2 n - 1) x + n - 2 = 0

What are the solutions to the equation X^2+4X-6=0 ?
The solutions to the equation X^2+4X-6=0 are X=-2+sqrt(10),X=-2-sqrt(10)
Find the zeros of X^2+4X-6=0
The zeros of X^2+4X-6=0 are X=-2+sqrt(10),X=-2-sqrt(10)