What are the solutions to the equation 0=2x^2-8x+6 ?

The solutions to the equation 0=2x^2-8x+6 are x=3,x=1

Find the zeros of 0=2x^2-8x+6

The zeros of 0=2x^2-8x+6 are x=3,x=1

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0 = 2 x^{2} - 8 x + 6

x = 3, x = 1

Solution steps

0 = 2 x^{2} - 8 x + 6

Switch sides

2 x^{2} - 8 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 \cdot 6 = 4

x_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 2}

x = \frac{- ( - 8 ) + 4}{2 \cdot 2} : 3

x = \frac{- ( - 8 ) - 4}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = 3, x = 1

0 = 2 x^{2} - 8 x + 5

x, x^{2} - k x + 4 = 0

x^{2} - 1 x

2 x (x + 1) = 12 - 2 (x - 9)

x^{2} - x - 36 = 0

What are the solutions to the equation 0=2x^2-8x+6 ?
The solutions to the equation 0=2x^2-8x+6 are x=3,x=1
Find the zeros of 0=2x^2-8x+6
The zeros of 0=2x^2-8x+6 are x=3,x=1