What are the solutions to the equation 9x^2-4=7x^2-7x ?

The solutions to the equation 9x^2-4=7x^2-7x are x= 1/2 ,x=-4

Find the zeros of 9x^2-4=7x^2-7x

The zeros of 9x^2-4=7x^2-7x are x= 1/2 ,x=-4

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9 x^{2} - 4 = 7 x^{2} - 7 x

x = \frac{1}{2}, x = - 4

Decimal Notation

x = 0.5, x = - 4

Solution steps

9 x^{2} - 4 = 7 x^{2} - 7 x

Move

7 x

to the left side

9 x^{2} - 4 + 7 x = 7 x^{2}

Move

7 x^{2}

to the left side

2 x^{2} + 7 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 4) = 9

x_{1, 2} = \frac{- 7 \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 9}{2 \cdot 2}, x_{2} = \frac{- 7 - 9}{2 \cdot 2}

x = \frac{- 7 + 9}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 7 - 9}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 4

2 x^{2} = - 72

p, 4 x^{2} - 9 = (p x + t) (p x - t)

a^{2} - 2 a + 2 = 0

- 2 x + (x^{2} - 2 x - 3) = - 3

x^{2} - 4 x - 12 = 0

What are the solutions to the equation 9x^2-4=7x^2-7x ?
The solutions to the equation 9x^2-4=7x^2-7x are x= 1/2 ,x=-4
Find the zeros of 9x^2-4=7x^2-7x
The zeros of 9x^2-4=7x^2-7x are x= 1/2 ,x=-4