What are the solutions to the equation w^2-w-2=0 ?

The solutions to the equation w^2-w-2=0 are w=2,w=-1

Find the zeros of w^2-w-2=0

The zeros of w^2-w-2=0 are w=2,w=-1

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w^{2} - w - 2 = 0

w = 2, w = - 1

Solution steps

w^{2} - w - 2 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

w_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, w_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

w = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

w = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

w = 2, w = - 1

x^{2} + 2 = 7

\frac{x + 1}{4} - \frac{x ^{2} - 2}{3} = \frac{x ^{2} - 2}{6} + 1

x^{2} - 14 x + 44 = 0

2 x^{2} = 338

2 x^{2} - 20 x + 50 = - 128

What are the solutions to the equation w^2-w-2=0 ?
The solutions to the equation w^2-w-2=0 are w=2,w=-1
Find the zeros of w^2-w-2=0
The zeros of w^2-w-2=0 are w=2,w=-1