What are the solutions to the equation -(x-2)^2+4=-5 ?

The solutions to the equation -(x-2)^2+4=-5 are x=5,x=-1

Find the zeros of -(x-2)^2+4=-5

The zeros of -(x-2)^2+4=-5 are x=5,x=-1

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- (x - 2)^{2} + 4 = - 5

x = 5, x = - 1

Solution steps

- (x - 2)^{2} + 4 = - 5

Move

4

to the right side

- (x - 2)^{2} = - 9

Divide both sides by

- 1

(x - 2)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 9 : x = 5

Solve

x - 2 = - 9 : x = - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

4 x^{2} - 12 x + 16 = 0

x^{2} = 6 x - 7

y, z = 1 - y^{2}

7 x^{2} - 64 = 0

x^{2} + \frac{32}{3} = 0

What are the solutions to the equation -(x-2)^2+4=-5 ?
The solutions to the equation -(x-2)^2+4=-5 are x=5,x=-1
Find the zeros of -(x-2)^2+4=-5
The zeros of -(x-2)^2+4=-5 are x=5,x=-1