What are the solutions to the equation solvefor s,12x^2-8sx+s^2=0 ?

The solutions to the equation solvefor s,12x^2-8sx+s^2=0 are s=6x,s=2x

Find the zeros of solvefor s,12x^2-8sx+s^2=0

The zeros of solvefor s,12x^2-8sx+s^2=0 are s=6x,s=2x

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solve for

s, 12 x^{2} - 8 s x + s^{2} = 0

s = 6 x, s = 2 x

Solution steps

12 x^{2} - 8 s x + s^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

s^{2} - 8 x s + 12 x^{2} = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 8 x ) \pm ( - 8 x ) ^{2} - 4 \cdot 1 \cdot 12 x ^{2}}{2 \cdot 1}

Simplify

(- 8 x)^{2} - 4 \cdot 1 \cdot 12 x^{2} : 4 x

s_{1, 2} = \frac{- ( - 8 x ) \pm 4 x}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 8 x ) + 4 x}{2 \cdot 1}, s_{2} = \frac{- ( - 8 x ) - 4 x}{2 \cdot 1}

s = \frac{- ( - 8 x ) + 4 x}{2 \cdot 1} : 6 x

s = \frac{- ( - 8 x ) - 4 x}{2 \cdot 1} : 2 x

The solutions to the quadratic equation are:

s = 6 x, s = 2 x

p^{2} - 16 p - 52 = 0

x^{2} + 8 + 16 = 0

x^{2} - 6 + 8 = 0

\frac{1}{2} x^{2} - x - \frac{1}{3} = 0

1 + 4 + 7 + 3 n - 2 = \frac{n ( 3 n - 1 )}{2}

What are the solutions to the equation solvefor s,12x^2-8sx+s^2=0 ?
The solutions to the equation solvefor s,12x^2-8sx+s^2=0 are s=6x,s=2x
Find the zeros of solvefor s,12x^2-8sx+s^2=0
The zeros of solvefor s,12x^2-8sx+s^2=0 are s=6x,s=2x