What are the solutions to the equation x^2-3x-44=-3x+5-3x+5 ?

The solutions to the equation x^2-3x-44=-3x+5-3x+5 are x=6,x=-9

Find the zeros of x^2-3x-44=-3x+5-3x+5

The zeros of x^2-3x-44=-3x+5-3x+5 are x=6,x=-9

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x^{2} - 3 x - 44 = - 3 x + 5 - 3 x + 5

x = 6, x = - 9

Solution steps

x^{2} - 3 x - 44 = - 3 x + 5 - 3 x + 5

Refine

x^{2} - 3 x - 44 = - 6 x + 10

Move

10

to the left side

x^{2} - 3 x - 54 = - 6 x

Move

6 x

to the left side

x^{2} + 3 x - 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 54 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 54) = 15

x_{1, 2} = \frac{- 3 \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 15}{2 \cdot 1}, x_{2} = \frac{- 3 - 15}{2 \cdot 1}

x = \frac{- 3 + 15}{2 \cdot 1} : 6

x = \frac{- 3 - 15}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 6, x = - 9

y, x^{4} - 7 x y^{2} + y = 7

x^{2} + (\frac{5}{13})^{2} = 1

x, f = 3 x^{2} + 2 y + 5

x^{2} = - 9 x - 18

z^{2} - 6 z + 13 = 0

What are the solutions to the equation x^2-3x-44=-3x+5-3x+5 ?
The solutions to the equation x^2-3x-44=-3x+5-3x+5 are x=6,x=-9
Find the zeros of x^2-3x-44=-3x+5-3x+5
The zeros of x^2-3x-44=-3x+5-3x+5 are x=6,x=-9