What are the solutions to the equation -2x^2-6x+9=0 ?

The solutions to the equation -2x^2-6x+9=0 are x=-(3(1+sqrt(3)))/2 ,x=(3(sqrt(3)-1))/2

Find the zeros of -2x^2-6x+9=0

The zeros of -2x^2-6x+9=0 are x=-(3(1+sqrt(3)))/2 ,x=(3(sqrt(3)-1))/2

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- 2 x^{2} - 6 x + 9 = 0

x = - \frac{3 ( 1 + 3 )}{2}, x = \frac{3 ( 3 - 1 )}{2}

Decimal Notation

x = - 4.09807 \dots, x = 1.09807 \dots

Solution steps

- 2 x^{2} - 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 2 ) \cdot 9}{2 ( - 2 )}

(- 6)^{2} - 4 (- 2) \cdot 9 = 63

x_{1, 2} = \frac{- ( - 6 ) \pm 6 3}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 3}{2 ( - 2 )}, x_{2} = \frac{- ( - 6 ) - 6 3}{2 ( - 2 )}

x = \frac{- ( - 6 ) + 6 3}{2 ( - 2 )} : - \frac{3 ( 1 + 3 )}{2}

x = \frac{- ( - 6 ) - 6 3}{2 ( - 2 )} : \frac{3 ( 3 - 1 )}{2}

The solutions to the quadratic equation are:

x = - \frac{3 ( 1 + 3 )}{2}, x = \frac{3 ( 3 - 1 )}{2}

x^{2} + x = 182

x, x^{2} - 3 x - 2 = 0

3 u^{2} - 21 u = 0

x^{2} = 7 x + 1

3 x^{2} + 243 = 60 x

What are the solutions to the equation -2x^2-6x+9=0 ?
The solutions to the equation -2x^2-6x+9=0 are x=-(3(1+sqrt(3)))/2 ,x=(3(sqrt(3)-1))/2
Find the zeros of -2x^2-6x+9=0
The zeros of -2x^2-6x+9=0 are x=-(3(1+sqrt(3)))/2 ,x=(3(sqrt(3)-1))/2