What are the solutions to the equation 46=-16t^2+50t+10 ?

The solutions to the equation 46=-16t^2+50t+10 are t= 9/8 ,t=2

Find the zeros of 46=-16t^2+50t+10

The zeros of 46=-16t^2+50t+10 are t= 9/8 ,t=2

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46 = - 16 t^{2} + 50 t + 10

t = \frac{9}{8}, t = 2

Decimal Notation

t = 1.125, t = 2

Solution steps

46 = - 16 t^{2} + 50 t + 10

Switch sides

- 16 t^{2} + 50 t + 10 = 46

Move

46

to the left side

- 16 t^{2} + 50 t - 36 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 ( - 16 ) ( - 36 )}{2 ( - 16 )}

5 0^{2} - 4 (- 16) (- 36) = 14

t_{1, 2} = \frac{- 50 \pm 14}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 50 + 14}{2 ( - 16 )}, t_{2} = \frac{- 50 - 14}{2 ( - 16 )}

t = \frac{- 50 + 14}{2 ( - 16 )} : \frac{9}{8}

t = \frac{- 50 - 14}{2 ( - 16 )} : 2

The solutions to the quadratic equation are:

t = \frac{9}{8}, t = 2

2 n x^{2} = x + \frac{1}{n}

- x^{2} - 5 x - 4 = 0

x^{2} - 10 x = 10

x^{2} + 8 x + 12 = 0

4 (x + 1)^{2} = 36

What are the solutions to the equation 46=-16t^2+50t+10 ?
The solutions to the equation 46=-16t^2+50t+10 are t= 9/8 ,t=2
Find the zeros of 46=-16t^2+50t+10
The zeros of 46=-16t^2+50t+10 are t= 9/8 ,t=2