What are the solutions to the equation 2(x-4)^2=2 ?

The solutions to the equation 2(x-4)^2=2 are x=5,x=3

Find the zeros of 2(x-4)^2=2

The zeros of 2(x-4)^2=2 are x=5,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 (x - 4)^{2} = 2

x = 5, x = 3

Solution steps

2 (x - 4)^{2} = 2

Divide both sides by

2

(x - 4)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 1 : x = 5

Solve

x - 4 = - 1 : x = 3

The solutions to the quadratic equation are:

x = 5, x = 3

7 a + 28 b

lo g_{2} (4096)

5 [3 (x + 4) - 2 (1 - x)] - x - 15 = 14 x + 45

x^{2} - 10 x

What are the solutions to the equation 2(x-4)^2=2 ?
The solutions to the equation 2(x-4)^2=2 are x=5,x=3
Find the zeros of 2(x-4)^2=2
The zeros of 2(x-4)^2=2 are x=5,x=3