What are the solutions to the equation 2(x-4)^2-5=3 ?

The solutions to the equation 2(x-4)^2-5=3 are x=6,x=2

Find the zeros of 2(x-4)^2-5=3

The zeros of 2(x-4)^2-5=3 are x=6,x=2

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2 (x - 4)^{2} - 5 = 3

x = 6, x = 2

Solution steps

2 (x - 4)^{2} - 5 = 3

Move

5

to the right side

2 (x - 4)^{2} = 8

Divide both sides by

2

(x - 4)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 4 : x = 6

Solve

x - 4 = - 4 : x = 2

The solutions to the quadratic equation are:

x = 6, x = 2

- 0.008 x^{2} + 250 = 0.0016 x^{2} + 0.04 x + 150

x^{2} - 5 = 3

4 x^{2} = - 7 x + 15

9 x^{2} - 6 x = - 1

x^{2} + 2 x + 3 = 0

What are the solutions to the equation 2(x-4)^2-5=3 ?
The solutions to the equation 2(x-4)^2-5=3 are x=6,x=2
Find the zeros of 2(x-4)^2-5=3
The zeros of 2(x-4)^2-5=3 are x=6,x=2