What are the solutions to the equation (x-4)(x+4)=9 ?

The solutions to the equation (x-4)(x+4)=9 are x=5,x=-5

Find the zeros of (x-4)(x+4)=9

The zeros of (x-4)(x+4)=9 are x=5,x=-5

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(x - 4) (x + 4) = 9

x = 5, x = - 5

Solution steps

(x - 4) (x + 4) = 9

Expand

(x - 4) (x + 4) : x^{2} - 16

x^{2} - 16 = 9

Move

9

to the left side

x^{2} - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 25 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 25) = 10

x_{1, 2} = \frac{- 0 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 10}{2 \cdot 1}, x_{2} = \frac{- 0 - 10}{2 \cdot 1}

x = \frac{- 0 + 10}{2 \cdot 1} : 5

x = \frac{- 0 - 10}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 5, x = - 5

(x - 4) (x + 4) = 0

- 2 x^{2} + 16 x - 29

x^{2} + 54 = 0

A = π r^{2}, r

8 x^{2} + 8 x

What are the solutions to the equation (x-4)(x+4)=9 ?
The solutions to the equation (x-4)(x+4)=9 are x=5,x=-5
Find the zeros of (x-4)(x+4)=9
The zeros of (x-4)(x+4)=9 are x=5,x=-5